Straight line: Difference between revisions

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1.
1.
A basis of allocating total costs or income equally across successive time periods.
A basis of allocating total costs or income equally across successive time periods.


For example, a fixed asset has a cost of $12m, an expected disposal value of $2m and an expected useful life of 4 years.
For example, a fixed asset has a cost of $12m, an expected disposal value of $2m and an expected useful life of 4 years.
The total expected accounting cost = $12m - $2m = $10m.
The total expected accounting cost = $12m - $2m = $10m.


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The net book value of the fixed asset would be (at the end of each year):
The net book value of the fixed asset would be (at the end of each year):
Year 1 = 12.0 - 2.5 = $9.5m.
Year 1 = 12.0 - 2.5 = $9.5m.
Year 2 = 9.5 - 2.5 = $7.0m.
Year 2 = 9.5 - 2.5 = $7.0m.
Year 3 = 7.0 - 2.5 = $4.5m.
Year 3 = 7.0 - 2.5 = $4.5m.
Year 4 = 4.5 - 2.5 = $2.0m.
Year 4 = 4.5 - 2.5 = $2.0m.


Using a straight line basis of depreciation, the net book value of a retained asset will often fall to zero.
Using a straight line basis of depreciation, the net book value of a retained asset will often fall to zero.
(But it would never be depreciated to a negative value of course.)
(But it would never be depreciated to a negative value of course.)


2.
2.
An estimation method which assumes a straight line relationship between the items under review.
An estimation method which assumes a straight line relationship between the items under review.
Sometimes known as Linear interpolation.
Sometimes known as Linear interpolation.
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* [[Reducing balance]]
* [[Reducing balance]]
* [[Sum of the digits]]
* [[Sum of the digits]]

Revision as of 08:34, 20 August 2013

1.

A basis of allocating total costs or income equally across successive time periods.

For example, a fixed asset has a cost of $12m, an expected disposal value of $2m and an expected useful life of 4 years.

The total expected accounting cost = $12m - $2m = $10m.

Allocated on a straight line basis over 4 years, the depreciation charge in each year would be $10m/4 = $2.5m.

The net book value of the fixed asset would be (at the end of each year):

Year 1 = 12.0 - 2.5 = $9.5m.

Year 2 = 9.5 - 2.5 = $7.0m.

Year 3 = 7.0 - 2.5 = $4.5m.

Year 4 = 4.5 - 2.5 = $2.0m.

Using a straight line basis of depreciation, the net book value of a retained asset will often fall to zero. (But it would never be depreciated to a negative value of course.)


2.

An estimation method which assumes a straight line relationship between the items under review. Sometimes known as Linear interpolation.

See also